Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
a → g(c)
g(a) → b
f(g(X), b) → f(a, X)
Q is empty.
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
a → g(c)
g(a) → b
f(g(X), b) → f(a, X)
Q is empty.
Using Dependency Pairs [1,13] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:
F(g(X), b) → A
F(g(X), b) → F(a, X)
A → G(c)
The TRS R consists of the following rules:
a → g(c)
g(a) → b
f(g(X), b) → f(a, X)
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ EdgeDeletionProof
Q DP problem:
The TRS P consists of the following rules:
F(g(X), b) → A
F(g(X), b) → F(a, X)
A → G(c)
The TRS R consists of the following rules:
a → g(c)
g(a) → b
f(g(X), b) → f(a, X)
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
We deleted some edges using various graph approximations
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ EdgeDeletionProof
↳ QDP
↳ DependencyGraphProof
Q DP problem:
The TRS P consists of the following rules:
F(g(X), b) → F(a, X)
F(g(X), b) → A
A → G(c)
The TRS R consists of the following rules:
a → g(c)
g(a) → b
f(g(X), b) → f(a, X)
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
The approximation of the Dependency Graph [13,14,18] contains 1 SCC with 2 less nodes.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ EdgeDeletionProof
↳ QDP
↳ DependencyGraphProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
F(g(X), b) → F(a, X)
The TRS R consists of the following rules:
a → g(c)
g(a) → b
f(g(X), b) → f(a, X)
Q is empty.
We have to consider all minimal (P,Q,R)-chains.